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If x1 and x2 are irrational numbers, can x1^x2 be a rational?

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If x1 and x2 are irrational numbers, can x1^x2 be a rational?
posted Jan 16, 2018 by Salil Agrawal

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1 Answer

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We know that e is a transcendental and irrational number.
Also natural logarithm of any rational number is irrational.
This means e and ln(any rational number) are both irrational
Then e^(ln (2)) = 2 which is rational.
So it's possible to have a rational answer for irrational^irrational.

answer Feb 3, 2018 by Tejas Naik



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