If the sum of the first 10^10^100 odd numbers is of the form a^b^a for positive integers a and b then find a+b = ?

Question

1, 2, 3, 4, 5, 6, 7, 8, 9, 10
The above are the first 10 positive integers. The product of the numbers before the number __ is the same as the product of the numbers after that number.

Answer 1

Sum of first 10^10^100 odd numbers = 10^20^100
10^20^100 = 10^10240000000000^10 ==> a^b^a
Where a = 10 & b = 10240000000000
Therefore a + b = 10240000000010.