a = 2 & b = 6 2^6 + 6^2 = 64 + 36 = 100.
Find the number of ordered pairs (x,y) satisfying the system of equations -
x + y^2 = 12 x^2 + y = 12
a^2 + b^2 = a.b It is obvious that a=b=0 satisfies the equation above. But is there another pair of real numbers satisfying this equation?
