What is the ratio of the area of big pentagon and small pentagon in the following image?
The area of the pentagon are proportional to the square of its sides. So if Big Pentagon has side a Then we can find the side of Small Pentagon as = (a/4)*((5^0.5) - 1)^2 by knowing that the internal angles of a Regular Pentagon is 108 degrees and Basic Trignometry. Now required ratio = [Area of Big Pentagon / Area of Small Pentagon] = a^2/((a/4)^2*(((5^0.5) - 1)^2)^2) = 2 / ( 7 - (3*5^0.5)).
The area of the small regular pentagon is A. The area of the big regular pentagon is B. What is A/B?
Two parabolas with vertical axes of symmetry share each other's vertex, and are contained between horizontal lines that go through their vertices.
What is the ratio of blue area (intersection) to the grey area in the image?
What is the ratio of the blue shaded area to the orange shaded area in the following image?
What is the ratio of area of large square to the area of smaller square in the following image?
If in each square, the blue and red areas are equal then find out the ratio of radius between big and small circle?
