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In the equation shown below, A, B, C, D, and E are 5 consecutive positive integers. What are they?

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A*A + B*B + C*C = D*D + E*E

posted Sep 3, 2014 by Pushpak Chauhan

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3 Answers

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A = 10
B=11
C=12
D=13
E=14

answer Sep 25, 2014 by Muniprasad
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Let a, a+1, a+2. a+3 & a+4 be the numbers.
a^2+(a+1)^2+(a+2)^2=(a+3)^2+(a+4)^2;
solve this quadratic eqn. we get
a=10
Numbers are 10 11 12 13 14

answer Oct 22, 2015 by Naveen Chopra
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10, 11, 12, 13, 14

10*10 + 11*11 + 12*12 = 13*13 + 14*14 = 365

answer Dec 9, 2015 by anonymous



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