Can you find digits that make equations true in the following alphametic puzzles (cryptarithms)?

RE + MI = FA
DO + SI = MI
LA + SI = SOL

1 Answer

15 + 47 = 62
30 + 17 = 47
92 + 17 = 109

R=S?

answer Feb 9, 2016 by anonymous

The real answer:
27 + 56 = 83
40 + 16 = 56
93 + 16 = 109

commented May 12, 2016 by anonymous

Similar Puzzles

0 votes

0 0 0 = 6
1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6

You can use any mathematical symbols in the space provided to make all above algebraic expressions true.

0 votes

+2 votes

Can you solve the below alphametic riddle by replacing letters of words by a number so that the below equation holds true?

BASE +
BALL
---------
GAMES

+3 votes

0 0 0 = 6
1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6

Example:
2+2+2=6

+1 vote

ZY = XZ - WV
UT = YV - ST
WY = ZU - RZ
QX = PX - QV
QL = LQ - WP
SV = XT - YR

Note: You can using only 8 digits. (i.e. more than one alphabets will be mapped to same numerical value)

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