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Using the digits 123456789, find a number such that the left most digit is divisible by 1, two left most digits by 2...

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Given the number 123456789. Find a permutation of the number's digits such, that the left most digit is evenly divisible by 1, the two left most digits are evenly divisible by 2, the three left most digits are divisibly by 3 and so on?

posted Jan 15, 2019 by anonymous

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