In a single throw of two dice what is the probability of not getting the same number of both the dice?

Answer 1

There are 36 total possible outcomes of which only 6 are unfavorable to the given event [(1,1) (2,2) (3,3) (4,4) (5,5) (6,6)]
Therefore the required probability = 1 - (6/36) = 1 - (1/6) = (5/6) = 83.33%.