How many 5 digit numbers can be formed by using 3, 4, 5, 6, 7, if 6 is necessarily taken at hundred's place and 4 is not allowed at unit's place? Note : Repetition of numbers is not allowed.
6 is necessarily taken at hundred's place and 4 is not allowed at unit's place, hence number of options = 3*2*1*1*3 = 18
How many numbers of five digits can be formed by using 1,2,3,4,5, if 4 is necessarily taken at hundred's place and 2 is not allowed at unit's place. Repetition of number is not allowed.
How many numbers can be formed from 1, 2, 3, 4, 5 (without repetition), when the digit at the units place must be greater than that in the ten's place?
How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 0, which are divisible by 5 and none of the digits is repeated?
If repetition of numbers is not allowed then how many numbers of five digits can be formed by using 1,2,3,4,5. If 4 is necessarily taken at hundred's place and 2 is not allowed at unit's place
