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What is the value of x^3 + y^3 + z^3 - 3xyz, when x = 2, z = -3 and y = 1?

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What is the value of x^3 + y^3 + z^3 - 3xyz, when x = 2, z = -3 and y = 1?
posted Jan 7, 2020 by Deepak Chitragar

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1 Answer

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x^3 + y^3 + z^3 - 3xyz = 0
given x = 2, z = -3 and y = 1

answer Jan 8, 2020 by Tejas Naik



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