If 15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take, if 3 women do as much work as 2 men?
15 men take 21 days of 8 hrs. each to do a piece of work. How many days of 6 hrs. each would it take for 21 women if 3 women do as much work as 2 men? : Find the no. of man-hrs to complete the job 15 * 21 * 8 = 2520 man hrs : 2 man-hrs = 3 women-hrs therefore 1 women-hr = 2/3 man-hr : let d = no. days for these women to do the job 21 * 2/3 * 6d = 2520 84d = 2520 d = 30 days
30 days im not 100% sure.. but i used de logic M1*D1*T1=M2*D2*T2 Given M1=15, D1=21, T1=8hrs, M2=14(21 women=14 men),T2=6hrs, Therefore, D2= M1*D1*T1 / M2*T2=30
If 6 men and 8 women can do a piece of work in 10 days and 4 men and 7 women can do it in 12 days, how many days will 4 men and 12 women take to do half of work?
20 women work on a certain project for 4 days and completes one-tenth of it. 15 men work for the next 'x' days and completes one-fifth of it, if after (4+x) days, 20 women and 15 men work together and completes the remaining work in 12 days, then how many days will 15 men take to complete the whole work?
If 9 boy working 15/2 hours a day can finish a work in 20 days, then how many days will be taken by 12 boy working 6 hours a day to finish the work, it being given than 3 boy of latter type work as much as 2 boy of he former type in the same.
If A men working A hours a day can do A units of a work in A days, then how many units of work can be completed by B men working B hours per day.
10 men and 15 women complete half of the work in 12 days and 6 men and 15 women complete one third of the work in 10 days. How many days are required to complete the same full work by taking 10 men and 30 women?
