Only one two-digit square number has digits which themselves are square numbers. What is the number?

Question

What is the 5 digit number in which the sum of the first two digits is one less than the third, the third is double the fourth, the fourth is double the last, the third is the product of the fourth and fifth, the second is five more than the first and the first is one-eighth third and also one-fourth of the fourth?

Answer 1

49=7^2
4=2^2
9=3^2