Lines AB and CD intersect in the interior of a circle, as shown below. If arc AC measures 80 degrees, and arc DB measures 140 degrees, what is the measure of angle DXB?
Angle DXB=180-angle DXA= angle XAD+angle XDA Angle XAD (same as DAB)=140/2=70 deg Angle XDA (same as ADC)= 80/2=40 deg So Angle DXB=70+40=110 deg
Quadrilateral ABCD has AD = BC, ∠A + ∠B = 90°, AB = 20, CD = 10, as shown below.
What is the area of ABCD?
If the medians of triangle ABC intersect at P , then evaluate
AB^2+AC^2+BC^2 ---------------- PA^2+PB^2+PC^2
In trapezoid ABCD, the sides AB and CD are parallel and AB > CD. Point P is in the interior, dividing the trapezoid into 4 triangles with areas CPD = 2, CPB = 3, BPA = 4, APD = 5. What is AB/CD equal to?
If AF=1 and AB=AC=7 in the given image then what would be the radius of grey circle?
