Given positive real numbers x, y, and z that satisfy the following system of equations: x² + xy + y² = 9, y² + yz + z² = 4, z² + zx + x² = 1,
Find x + y + z
x=1 y=2 z=0
Sooo........
x+y+z=1+2+0
But I calculated the first equation and that equaled 9.
How many integer solutions are there to the system of equations below and which are those solutions?
x^2+y-z = 42 x+y^2-z = 18
If x, y, z are 3 non zero positive integers such that x+y+z = 8 and xy+yz+zx = 20, then What would be minimum possible value of x*y^2*z^2
Find the number of ordered pairs (x,y) satisfying the system of equations -
x + y^2 = 12 x^2 + y = 12
