A sack contains 4 different colored balls (blue, yellow, red, and pink) of which 14 balls are not blue, 16 balls are not yellow, 24 balls are not red, and 12 balls are not pink. How many balls are in the sack?
No solution
Let the total number of balls is t. We have: b + y + r + p = t Also we have: 14 = t - b 16 = t - y 24 = t - r 12 = t - p Sum up the above 4 equations: 66 = 4t - (b+y+r+p) 66 = 3t 22 = t The answer would be 22 but there is a contradiction where it say 24 balls are not red. It means the total should be greater than 24. Considering the above there is no solution.
A bag contains 4 yellow, 5 red, 3 green and 4 black balls. If 4 balls are drawn randomly without replacement, what is the probability that the balls drawn contains balls of different colors?
In a box, there is a jumble of 7 red balls, 6 blue balls, 5 green balls, and 4 yellow balls. What is the minimum number of balls will you have to pick up so that you have at least 4 balls of the same colour?
A box contains 4 red balls, 6 green and 8 black balls. Three balls are drawn at random find the probability that three balls are of different color?
A box contains 4 blue, 3 red, 5 green and 6 yellow marbles. If three marbles are drawn at random, what is the probability that at least one is green?
In a bag total of blue and red balls is equal to six times the yellow balls and blue balls are two-fifth of total of yellow and red balls. If 44 blue balls are there, then how many balls are there in the bag?
