If 1/x + 1/y = 1/3 1/x + 1/z = 1/5 1/y + 1/z = 1/7 then x/y = ??
x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be
Find the value of x and y if
[40/(x+y)] + [2/(x-y)] = 5 [25/(x+y)] - [3/(x-y)] = 1