If 1/x + 1/y = 1/3; 1/x + 1/z = 1/5; 1/y + 1/z = 1/7 then x/y = ??

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If
1/x + 1/y = 1/3
1/x + 1/z = 1/5
1/y + 1/z = 1/7
then
x/y = ??

posted Jun 13, 2015 by anonymous

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1 Answer (Check Answer ▼)

Let 1/x = a , 1/y = b , 1/z = c
The new equations are
a + b = 1/3 ----->1
a + c = 1/5 ------->2
b +c = 1/7 ------->3

By solving 2 and 3, a-b = 2/35 ---> 4

Solving for a , we get a= 41/210
Substitute a in equation 4 , we get value of b as 29/210

X/Y = 1/a * b = 29/210 * 210 /41 == 29/41
Ans : X/Y = 29/41

answer Jun 15, 2015 by Muthulakshmi K

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If 1/x + 1/y = 1/3; 1/x + 1/z = 1/5; 1/y + 1/z = 1/7 then x/y = ??

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