The sum of a non zero number, its square, its cube and its four power is 7380. If five power of the number is added to 7380 and divided by the number , then what will be the qoutient ?
its ..7381.....
x + x^2 + x^3 + x^4 = 7380 Add x^5 on both the side We get x + x^2 + x^3 + x^4 + x^5 = 7380 + x^5 Now divide by x on both the side (x + x^2 + x^3 + x^4 + x^5)/x = (7380 + x^5)/x 1 + x + x^2 + x^3 + x^4 = (7380 + x^5)/x 1+7380 = 7381
The cube of sum of a positive integer and its square is a five digit number. What will be the sum of cubes of sum of integer and its square for all possible value of integer ?
A four digit positive number having all non-zero distinct digits is such that the product of all the digits is least. If the difference of hundreds digit and tens digit is 1. How many possibilities are there of such number?
