The cube of sum of a positive integer and its square is a five digit number. What will be the sum of cubes of sum of integer and its square for all possible value of integer ?
(a+a^2)^3=five digit number a= 5,6 satisfy the condition Therefore, (5+25)^3=27000 (6+36)^3=74088 sum of the above two numbers 74088+27000 =101088
For some positive integer k both 4^k and 5^k start with the same digit x in base 10 i.e. 4^k = x..... 5^k = x..... What is the sum of all possible values of x.
Let a be a single-digit positive integer. Let n be another positive integer that adjusts itself so that the unit's place digits of n and an + 1 are the same. Find the sum of all possible values of a.
A given parallelogram has sides measuring 7 and 9, and both its diagonals have integer lengths. Find the sum of all possible products of the lengths of the diagonals.
The sum of a non zero number, its square, its cube and its four power is 7380. If five power of the number is added to 7380 and divided by the number , then what will be the qoutient ?
