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You have 32 numbers. What is the least number of comparison needed to find the 2nd smallest out of them?

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You have 32 numbers. What is the least number of comparison needed to find the 2nd smallest out of them?
posted Nov 22, 2014 by anonymous

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1 Answer

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n + logn - 2

i.e. 35

answer Dec 19, 2014 by Shashi Kant



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