If x2 – 3x + 1 = 0, then find the value of x5 + 1/x5.
If (3!)^2 - (2!)^1 - (1!)^0 - 3! - 2! - 1! - 0! = 7 + x^2 then x^2 - 3x/2 - 4 = ?
The line 2x – y + 1 = 0 intersects the curve x2 + 3y = 19 at the points A and B. The perpendicular bisector of AB intersects the x-axis at the point C. Find the area of triangle ABC.