What will be the product of all the digit of the choosen number ?

Question

A five digit number is choosen in such a way that ten's place is one less than unit's place, hundred's place is one less than ten's place and similarly the other digits. Sum of all the digits of a number obtained by adding that choosen number and the number formed by reversing its digit is 40.

What will be the product of all the digit of the choosen number ?

Answer 1

23456 are the 5 digits, which is the chosen number
When reverse it becomes 65432
So
Sum of digits is 40
2+3+4+5+6+6+5+4+3+2=40
So product of chosen number digit is 2*3*4*5*6 = 720