Can you find out the number of chocolates they have right now?

Question

Aarav and Bhuvan have a certain number of chocolates with them. If Bhuvan gives one chocolate to Aarav, they will have equal number of chocolates. But if Aarav gives one chocolate to Bhuvan, then Aarav will be left with half the number of chocolates that Bhuvan has.

Can you find out the number of chocolates they have right now?

Answer 1

Aarav-4, Bhuvan-6.
Let 'x' be the no. of chocolates they will have after Bhuvan gives one chocolate.
Aarav actually has 'x-1', Bhuvan has 'x+1'.
When Aarav gives one to Bhuvan he will be left with 'x-2'
Given '(x-2)=((x+1)/2)'
On solving we get 'x=3'.
Hence Aarav-4, Bhuvan-6.

Comments

Your answer Aarav-4, Bhuvan-6. ===> is wrong
Let's test: A+1 = 5 and B-1= 5 ok!
But A-1 = 3 and B+1 = 7 ===> B/A = 7/3 (is wrong because not equal 2)
Your calculation is wrong. It should be:
x-2 = (x+2)/2 ===> in solving we get x=6
Hence Aarav = 6 - 1 = 5 and Bhuvan = 6 + 1 = 7

Answer 2

Answer: Aarav (A) = 5 and Bhuvan (B) = 7
A + 1 = B - 1 ----> A = B + 2
A - 1 = (B + 1) / 2 ---> B + 2 - 1 = (B + 1) / 2---> B-1 = (B + 1) / 2
solving A = 5 and B = 7
Check: A + 1 = B - 1 ----> 5+1=7-1 ok; A - 1 = (B+1)/2 ----> 5-1 = (7+1)/2 ---> ok

Answer 3

I thinks ans is: Aarav has:5 chocolates and Bhuvan has:7 chocolates