If x is an integer where x + x^(1/2) + x^(1/4) = 276 Then what would be the sum of all digits of the number y

Question

An integer x is selected in such a way that

x + x^(1/2) + x^(1/4) = 276

Then what would be the sum of all digits of the number y where

y = 100000 x^(1/4) + 1000 x^(1/2) + x 

Answer 1

X = 256
So
Y=400000+16000+256=416256
So sum of digits is 24

Answer 2

X = 256
given
y = 100000 x^(1/4) + 1000 x^(1/2) + x
then
Y=400000+16000+256=416256
So sum of digits = 24