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If y= (6+x)^2/(6-x)^2 is not a perfect integer and x is less than 6 and greater than 0, then what is the value y?

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If y= (6+x)^2/(6-x)^2 is not a perfect integer and x is less than 6 and greater than 0, then what is the value y?
posted Feb 9, 2016 by Tapesh Kulkarni

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