Taking AB= 6 BC=6 CD=6 Solving for white region Pie*(6^2) - pie*(3^2) =27*pie For blue region Pie*(9^2) - 27*pie =54*pie
By solving We get ratio as 2:1
let the full diameter be d then white area on both sides=(pi/4)*(2*d/3)^2-(pi/4)*(d/3)^2 = (pi/4)*d^2*(1/3) since blue area is whole area-white area it is =(pi/4)*d^2*-(pi/4)*d^2*(1/3) = (pi/4)*d^2*(2/3) thus blue area: white area = (2/3)/(1/3) or 2:1 ans
Rectangle ABCD has AB = 4 and BC = 8. Construct arc AE centered at B with E on side BC and construct arc CF centered at E with F along side AD. What is the area of AFCE, the region shaded in blue?
What is the % of the area of the blue region as compare to the whole?
What is the area of the blue region in the following image?
If ABCD is a square of area 1. E, F are mid points of AB and BC respectively. What is the area of blue region?
