If x+y+z = 7 2x-y+z = 4 Then 11y-10x = ??
By trial and error We get x=1 y=2 z=4 So 11*2 - 10*1 = 12 12 is the answer or 3z
x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be
If 1/x + 1/y = 1/3 1/x + 1/z = 1/5 1/y + 1/z = 1/7 then x/y = ??
