Total number of cases will be ::
x + y = z = 6 { x>=0 ,y>=0 ,z>=0 }
(6+3-1) C (3-1) =====
8 C =================28 2
hence the probaility of x=y=z=3 is 1/28
Since there are 28 options available and only one is favourable Therefore Probability = 1/28
If x(x+y) = y(y+z) = z(z+x) and x,y,z are positive integers. Then is it definitely true that x=y=z
If x, y, z are 3 non zero positive integers such that x+y+z = 8 and xy+yz+zx = 20, then What would be minimum possible value of x*y^2*z^2
There are 9 positive and 5 negative numbers. Four numbers are chosen at random and multiplied. What is the probability that the product is positive?