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The figure shows an isosceles triangle with AB = BC. The line DE cuts AC extended at F. If AD=5, CE=3 and EF=8 find DE.

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The figure shows an isosceles triangle with AB = BC. The line DE cuts AC extended at F. If AD=5, CE=3 and EF=8 find DE.

Find DE

posted Jun 18, 2015 by anonymous

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2 Answers

0 votes

enter image description here

answer Jun 25, 2015 by Ankit Kamboj
What are your "sine rules"? Where are the right angles?
commented Sep 16, 2015 by anonymous
Dear teuxe , sine rules applied here are
In a triangle ABC with sides a,b,c and its corresponding opposite angles A,B,C
{a/Sin(A)}={b/Sin(B)}={c/Sin(C)}  , holds for for any triangle , there are no right angles here ..
commented Sep 28, 2015 by Ankit Kamboj
0 votes

enter image description here

Draw a parallel line (EG) to AC.
DG = 2
The triangles DGE and DAF are similar.
DE/DG = DF/DA
x/2 = (8+x)/5
5x = 16 + 2x
3x = 16
x = 16/3

answer Aug 24, 2018 by Halil Akansel



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