The sum of 3 single digit numbers is 15 less than their product . If we subtract 2 from first given number then sum of these numbers will become 7 more than their product. Then what will be the product of given 3 numbers?
The numbers are 2,3,4 where 2 is the first number
let the three numbers be x,y,z then,x+y+z=x*y*z - 15 & (x-2)+y+z=(x-2)*y*z + 7 solving these we will get y*z=12 possiblities are {1,12} , {2,6} , {3,4} taking these {3,4} is satisfying the conditions giving x=2 so x*y*z=2*12=24
I am a three digit number. The product of the first and last digits is less than 49. The sum of the first two digits is less than 16. The difference of the first and last digits is greater than 0. The sum of the digits is greater than 6. The difference of the last two digits is equal to 2. The sum of the last two digits is equal to 6. The sum of the first and last digits is equal to 8.
A number (x) is 3 less than the thrice of other number (y) and sum of their squares is 97. What is the value of x and y respectively?
The sum of the digits of a two digit number is 15. If the number formed by reversing the digit is less than the original number by 27, find the original number.
What is the 5 digit number in which the sum of the first two digits is one less than the third, the third is double the fourth, the fourth is double the last, the third is the product of the fourth and fifth, the second is five more than the first and the first is one-eighth third and also one-fourth of the fourth?
