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Got segmentation fault while printing line number of file with %s and __LINE__ in c ?

+4 votes
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I have written print("%s", __LINE__); I get crashed. Can someone please explain why it is happened ?

posted Sep 17, 2013 by Vikram Singh

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I think it should be a printf() function.
commented Sep 17, 2013 by Satyabrata Mahapatra

2 Answers

+1 vote

Your error is for the in printf() function.
___LINE___ isn't a C style string, its an integral type (the exact flavor escapes me at the moment). %s is the wrong format. This is why, in C++, it is recommended that you avoid printf() and friends, and use iostreams instead.

answer Sep 17, 2013 by Satyabrata Mahapatra
+1 vote

%s is used for print string.

example= printf("%s", "_LINE_");

or char *p = "_LINE_" ;
    printf("%s",p);
answer Oct 3, 2013 by Dheerendra Dwivedi
Dheerandra: it may not work as __LINE__ prints the line number, so the intention here is different.
commented Oct 3, 2013 by Salil Agrawal
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