Question

Write a program to print the sum of the element of the array with the given below condition?

If the array has 6 and 7 in succeeding orders, ignore 6 and 7 and the numbers between them for the calculation of sum.

Array Elements - 10, 3, 6, 1, 2, 7, 9

Output: 22
i.e 10+3+9

Answer 1

        int[] num = { 10, 3, 6, 1, 4, 7, 9 };

        Console.Write("Enter your first number");
        int num1 = Convert.ToInt32(Console.ReadLine());

        Console.Write("Enter your second number");
        int num2 = Convert.ToInt32(Console.ReadLine());

        bool flage = false;
        int res = 0;
        foreach (var item in num)
        {

            if (item == num1)
            {
                flage = true;
            }
            if (flage == true)
            {
                if (item == num2)
                {
                    flage = false;
                }
                continue;
            }
            else
            {
                res += Convert.ToInt32(item);
            }
        }
        Console.WriteLine("Total=" + res);
        Console.ReadKey();

Comments

Good approach
Let see what different solution I can get from others.

---

That code has a corner case it wont give correct output when input is :Array Elements - 7,1,2,3,6
i corrected that and solution is :
package com.Milestone1.Arrays;
/** Write a program to print the sum of the elements of the array with the given below condition. If the array has 6 and 7 in succeeding orders, ignore 6 and 7 and the numbers between them for the calculation of sum.
Eg1) Array Elements - 10,3,6,1,2,7,9
O/P: 22   
[i.e 10+3+9]
*/
import java.util.Scanner;
public class Arrays_9 {

    public static void main(String[] args) {
            int n;
            Scanner sc = new Scanner(System.in);
            System.out.println("Enter the size of array:");
            n = sc.nextInt();
            int arr[] = new int[n];
            for(int i=0;i<n;i++){
                arr[i] = sc.nextInt();
               
            }
             sc.close();
            int num1 = 6;
            int num2 = 7;
            int sum = 0;
            boolean flag = false;
            for(int i : arr){
                if(i == num1){
                    flag = true;
                }
                if(flag == true){
                    if(i == num2){
                        flag = false;
                    }
                    continue;
                }
                else{
                    if(i == 7 ){
                        sum += 6+i;
                    }
                    else
                        sum += i;
                }
            }
            System.out.println("sum is "+sum);
           
           
           
    }

}

---

Can somebody explain me these lines:
else{
                    if(i == 7 ){
                        sum += 6+i;
                    }
                    else
                        sum += i;
                }

Answer 2

public class Assignment8 {
public static void main(String args[])
{
//checking testcases
// int[] arr= {1,2,3,4,6,8,9,7,2};
// int[] arr= {1,2,3,6,4,2,8,7,4};
// int[] arr= {7,1,2,3,6};
int[] arr= {1,2,3};

    int sixPos=-1;
    int sevenPos=-1;
    int sum=0;

    for(int i=0;i<arr.length;i++)
    {
        if(arr[i]==6) sixPos=i;
        if(arr[i]==7) sevenPos=i;
    }

    if(sevenPos==-1) sixPos=-1;

    for(int i=0;i<arr.length;i++)
    {
        if(sixPos!=-1 && i>=sixPos && i<=sevenPos) continue;
        sum+=arr[i];
    }

    System.out.println(sum);

}

}