Write a Java program to find the Sum of last digits of two given numbers?

Question

Rohit wants to add the last digits of two given numbers.
For example, If the given numbers are 267 and 154, the output should be 11.

Below is the explanation -
Last digit of the 267 is 7
Last digit of the 154 is 4
Sum of 7 and 4 = 11

Write a program to help Rohit achieve this for any given two numbers.

Note: The sign of the input numbers should be ignored. i.e.
if the input numbers are 267 and 154, the sum of last two digits should be 11
if the input numbers are 267 and -154, the sum of last two digits should be 11
if the input numbers are -267 and 154, the sum of last two digits should be 11
if the input numbers are -267 and -154, the sum of last two digits should be 11

Comments

Use string and solve this problem in O(1) constant complexity.

Answer 1

import java.io.*;
import  java.util.*;

// Read only region start
class UserMainCode
{

    public int addLastDigits(int input1,int input2){
        // Read only region end
        int sum=0;

        if((input1<10&&input1>0)&&(input2<10&&input2>0))
            sum=input1+input2;
        else if(input1<0&&input2<0)
        {
            input1=0-input1;
            input2=0-input2;
            input1=input1%10;
            input2=input2%10;
             sum=input1+input2;
        }
        else if(input1<0||input2<0)
        {
            input1=input1%10;
            input2=input2%10;
             sum=input1-input2;
            sum=sum%10;
        }
        else
        {
            while((input1 >10)||(input2 >10))
            {
              input1=input1%10;
              input2=input2%10;
              sum=input1+input2;
            }
        }

        System.out.print(sum);
        return sum;
    }
}

Answer 2

import java.io.*;
import java.util.*;
class UserMainCode
{
public int addLastDigits(int input1,int input2){
input1=Math.abs(input1%10);
input2=Math.abs(input2%10);
return Math.abs(input1+input2);
}
}

Even this works

Comments

its simple and easy to understand... thank you.