C: Find out the length of the sequence of repeated elements in a array of integers?

Question

Given a array of integers there is one that is repeated several time. How would you compute the length of the sequence of repeated elements.

Answer 1

#include<stdio.h>
#include<string.h>

int check_element(int str[],int curent_number,int index,int size)
{    
    int counter = 0;
    int sequence=1; 

    while(counter != size)
    {
        if(index == counter)
            counter++;

        if(counter != size)
        {
            if (curent_number == str[counter])
                sequence++;
        }

        counter++;
    }

    return sequence;
}

int main(void)
{
    int str[] = {2,1,3,4,5,6,1,66,66,96,7,77,28,22,1,29,1,90,98,1,92,1};
    int temp = 0,size;
    int i= 0;
    int sequence = 1;

    size = (sizeof(str) / sizeof(str[0]));

    while(i != size ) 
    {
        sequence = check_element(str,str[i],i,size);

        if(sequence !=  1)
        {
            printf(" number %d with repeating of %d times ",str[i],sequence);
            break;
        }
        else
        {
            i++;
        }
    }

    getchar();
    getchar();

    return 0;
}