Print source code using C program

Question

How to write a program in C or C++ which can print its source code on execution.

Answer 1

See this if it is helpful

#include <stdio.h>
char *program = "#include <stdio.h>%cchar *program = %c%s%c;%cint main()%c{%cprintf(program, 10, 34, program, 34, 10, 10, 10, 10, 10, 10);%c    return 0;%c}%c";
//what is this line doing, what is the use of %c and %s and what properties of %c and %s are being used here?
int main()
{
        printf(program, 10, 34, program, 34, 10, 10, 10, 10, 10, 10);
        //what is this print function doing, and how?
        return 0;
}

10 is newline
34 id "
Basically you rewrite the whole program in the program variable with 10 as newline and 34 as "....Rest is self explanatory.

Comments

Nice.

But will this work for all ?  what happens if i include one more line in this program, will this print all the lines without any change in your program ?

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Some work to be done but its one of the way

Answer 2

To make it generic you can use the __FILE__ macro so that it will take the current program's file and print the file content as output after reading.

Answer 3

It is possible through file handling. Save your program as Text.c and read it through your C code.

Comments

That may not be the purpose of the problem (myview) probably user is looking for some way by which he can print the program which he is executing.

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agree salil. let here it from owner.

Answer 4

It may be possible if you use file concepts to print the source code in your program....

Just read the saved program using file read command and them print it on the screen....
By this you could be able to print the source code..

Answer 5

Try this,

#include <stdio.h>

int main(int argc,char *argv[])
{
    char buf[100];
    if(argc != 2){
        printf("usage : exe <filename>\n");
        sprintf(buf,"cat %s",__FILE__);
    }else{
    sprintf(buf,"cat %s",argv[1]);
    }
    system(buf);
    return 0;
}