PHP side code for jQuery

Question

I use following code for jQuery.ajax to call php.

$.ajax('myserver.php")

It seems that one php file only work for one jquery ajax code, Is it possible to have more than one function or one return different result in one php file?

Your help is greatly appreciated,

Answer 1

You could either send information about which function you would like to call on the url parameter ($_GET)

$.ajax('myserver.php?function=ajaxRetrieveData');

or adding into data object ($_GET or $_POST) :

$.ajax({
 type: "POST",
 url: "myserver.php",
 data: { function: 'ajaxRetrieveData' }
});

and then using a router to find the function

myserver.php
$function = $_POST['function'];
$object->$function();

Please, do not use this code without properly validation.

Answer 2

If you use a framework like code igniter then you can define a single php file in which you can have separate controller functions which can act as different url parts for your different ajax calls.

CodeIgniter is a MVC framework and there are many MVC frameworks which offer the same feature.