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In socket programming using python how much time does the socket.recv() system call waits for the message?

+2 votes
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As per my understanding Receive system calls will be a blocking call of the code... it will not go ahead unless it receives the response from client .. my question is how would i set time in that? i want my code should wait only for few seconds then it has to come out from that

posted Mar 12, 2015 by Chirag Gangdev

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1 Answer

+1 vote
 
Best answer

You can make your socket as nonblocking in the folllowing way 

socket.setblocking(0)
while (retry_condition):
       data = socket.recv(512)
       ....

If you want to block the socket for certain time say 5 sec then leave your socket in blocking mode with the timeout say 

socket.setblocking(1) // 1 is for blocking and is default behavior also 
socket.settimeout(5.0)
...
answer Mar 13, 2015 by Salil Agrawal
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The problem description:

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But this cannot work since normal socket will not work and thus i thought of asyncore module in python. To use asyncore module again i will have to subclass asyncore.dispatcher. This class also contains connect() method.

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Please help since i have already spent 2 days digging it out. Sorry if could explain my problem very well.

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