top button
Flag Notify
    Connect to us
      Site Registration

Site Registration

Mohan's ages is 1/6 th of his father's age. The father's age will be twice of Suresh's ages, after 10 years...

+2 votes
516 views

Mohan's ages is 1/6 th of his father's age. The father's age will be twice of Suresh's ages, after 10 years. If Suresh's eight birhtday was celebrated 2 years before, what is Mohan's present age?

posted Dec 11, 2015 by anonymous

Share this puzzle
Facebook Share Button Twitter Share Button LinkedIn Share Button

2 Answers

+1 vote

5 years!
Father's age after 10 years = ((8+2)+10)*2 = 40
Father's present age = 30 years
Mohan's age = 30/6 = 5.

answer Dec 11, 2015 by anonymous
0 votes

Suresh' present age =8+2=10yrs=y
Father's present age=x yrs
Father's age after 10yrs
(x+10)=2(y+10)
(x+10)=2(10+10)
X=30yrs
Mohan's age=x/6=30/6=5yrs
Ans is 5yrs

answer Dec 11, 2015 by Jaikumar Bhatia



Similar Puzzles
–1 vote

Sum of the ages of a boy and his father is 77 years. Before 22 years Father's age was 10 times the age of the boy. What was the age of father at the time of birth of the child?

0 votes

The sum of the ages of A and B is 63 years. After 6 years, the age of B will be four times that of the A. What is the age of B ?

+1 vote

The ages of three children added together come to 20 and when multiplied together make 280. If the ages are multiplied together in 10 years time what will the answer be?

+1 vote

Sum of the ages of a boy and his father is 49 years. Before 11 years Father's age was 8 times the age of the boy. What was the age of father (in years) at the time of birth of the child?

...