On taking x = 1, 2, 3, 4, 5 respectively, we get y = 49/25, 4, 9, 25, 121 Only 49/25 is not a perfect square integer So answer is 49/25
An integer x is selected in such a way that
x + x^(1/2) + x^(1/4) = 276
Then what would be the sum of all digits of the number y where
y = 100000 x^(1/4) + 1000 x^(1/2) + x
A number (x) is 3 less than the thrice of other number (y) and sum of their squares is 97. What is the value of x and y respectively?
x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be
