X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?
4(1/20)+x(1/20+1/12)=1 12/60+x(3/60+5/60)=1 3/15+x(2/15)=1 2x/15=1-3/15 *15 2x=15-3 2x=12 /2 x=6 the answer is 6 days of working together and 4 days x alone 10 days in sum
A AND B WORK ANOTHER 10 DAYS TO FINISH THE BALANCE OF WORK 4/5
X started the work alone for 4 days, doing 4/20, or 1/5 of the work, leaving 4/5ths of the work to be done. Let n be the amount of days X and Y worked together. Then: n/20+n/12=4/5 3n+5n=48 8n=48 n=6 days of working together to finish the job ☺☺☺☺
Rahul and Maneesh working separately can do a piece of work in 9 days and 12 days respectively. If they work for a day alternately, Rahul beginning, in how many days, the work will be completed?
Dhoni can do a piece of work in 80 days. He works at it for 10 days and then Virat alone finishes the work in 42 days. How many number of days would be taken by the two together to finish the work.
P can do a work in 12 days. Q can do the same work in 8 days and R can do the same in 6 days. Q and R start the work and leave after 2 days. P finishes the remaining work in X days. What is the value of 1.1X?
Salil and Aarav can do a piece of work in 45 and 40 days respectively. They began the work together but Salil leaves after some days and Aarav finished the remaining work in 23 days. After how many days did Salil leave?
