Rahul and Maneesh working separately can do a piece of work in 9 days and 12 days respectively. If they work for a day alternately, Rahul beginning, in how many days, the work will be completed?
1/9+1/12=7/36 for 2 days. Hance total work will require 2*36/7=10.28 days.
Rahul does 1/9th of the work per day; Maneesh does 1/12th the work per day. Together, they do 1/9 + 1/12, or 7/36 of the work every 2 days. 1/7/36=36/7. 36/7 x 2=72/7, or 10 & 2/7 days, working alternately ☺☺☺☺
X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?
Salil and Aarav can do a piece of work in 45 and 40 days respectively. They began the work together but Salil leaves after some days and Aarav finished the remaining work in 23 days. After how many days did Salil leave?
If 9 boy working 15/2 hours a day can finish a work in 20 days, then how many days will be taken by 12 boy working 6 hours a day to finish the work, it being given than 3 boy of latter type work as much as 2 boy of he former type in the same.
P can do a work in 12 days. Q can do the same work in 8 days and R can do the same in 6 days. Q and R start the work and leave after 2 days. P finishes the remaining work in X days. What is the value of 1.1X?
8 woman and 12 men complete a certain piece of work in 9 days. Each woman takes twice the time taken by a man to finish the work. In how many days will 12 men finish the same work
