The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
4x-8+7x-8+9x-8=56 solving x=4 then present age=16,28 and36
(4x-8) + (7x-8) + (9x-8) = 56 4x + 7x + 9x - 24 = 56 20x = 56 + 24 = 80 x = 80 / 20 = 4 x = 4, Proportion is 4 : 7 : 9. So, their present ages= 16 , 28 and 36
The present ages of A,B and C are in proportions 3:4:5. Six years ago, the sum of their ages was 54. What is the product of their ages?
The present ages of A,B and C are in proportions 4:5:6. Eight years ago, the sum of their ages was 66. What is the sum of present age of A and C?
Solve this without paper and pen?
The ratio of present ages of Ram and Shyam is 4:3. If 10 years ago Ram was half of Shyam in age, what is the sum of their present ages?
The age of a father 10 years ago was thrice the age of his son . Ten years hence, the father's age will be twice that of his son. What is the ratio of their present ages?
