A 3 digit number is such that its unit digit is equal to the product of the other two digits which are prime. Also, the difference between its reverse and itself is 396. What is the sum of the three digits?
answer is 11... the num is 236... unit digit is 6... i.e; 2*3=6... difference b/w reverse of a num & itself i.e; 632-236=396... sum of digits in 236 is 11...
The sum of the digits of a three digit number is 12. If the hundreds digit is 3 times the tens digit and the tens digit is 1/2 the units digit, what is the tens digit of the number?
I am a three digit number. The product of the first and last digits is less than 49. The sum of the first two digits is less than 16. The difference of the first and last digits is greater than 0. The sum of the digits is greater than 6. The difference of the last two digits is equal to 2. The sum of the last two digits is equal to 6. The sum of the first and last digits is equal to 8.
I am a three digit number. The sum of the first and last digits is equal to 16. The sum of the first two digits is equal to 7. What am I?
The sum of the digits of a three digit number is 17, and the sum of the squares of its digits is 109. If we subtract 495 from the number, we shall get a number consisting of the same digits written in the reverse order. Find the number.
