Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 60° and 30° respectively. If the lighthouse is 144 m high, what is the distance between the two ships?
332 m
d=d1+d2 d1=144/tan 60=144/sqrt 3=83m approx d2=144/tan 30=144* sgrt 3= 249 m approx d=83+249=332 m approx
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30º and 45º respectively. If the lighthouse is 100 m high. What is the distance between the two ships ?
From a point A on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, the distance of point A from the foot of the tower is:
Two poles of height 12 m. and 4 m. are situated in such a way that the sun rays through the top of a pole also passes through the top of other. What is the distance between the poles? It is given that the sun rays make an angle of 45 degree with the horizon
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30º and 45º respectively. If the lighthouse is 100 m high, the distance between the two ships is:
