If we are to use the digits 7, 2, 1, 3, 0, 8, 4, 6 Smallest five digit number ====> 10234 [if 01234 is not allowed] Largest five digit number ====> 87643 The product then would be 10234 x 87643 = 896,938,462.
Arrange all the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9 to give four different square numbers. (You make a square number when you multiply something by itself, so 49 is square because it is 7 times 7)
How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 0, which are divisible by 5 and none of the digits is repeated?
