123, 132, 213, 231, 312 & 321. (2/6) ie 1/3 of them are even (132 & 312).
How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 0, which are divisible by 5 and none of the digits is repeated?
How many numbers can be formed from 1, 2, 3, 4, 5 (without repetition), when the digit at the units place must be greater than that in the ten's place?
