All possible four-digit numbers, with distinct digits using digits {1, 3, 4, 5, 6}. How many of them are divisible by 2?

Question

How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 0, which are divisible by 5 and none of the digits is repeated?

Answer 1

Total number of possible 4 digit numbers = 5 × 4 × 3 × 2 = 120
Number of 4 digit numbers that end with
either 4 or 6 (ie divisible by 2) = 120 × 2/5 = 48.