Find value of x^2 + 3xyz + 2y^ + 3z^2 where x = Mean, y = Median and z = Mode of: 83 87 93 97 110 48 114 119 87 118 122

1 Answer

2532195

Assumed it reads x^2 + 3xyz + 2y^2 + 3z^2 (<<2y^2>>)
122, 119, 118, 114, 110, 97, 93, 87, 87, 83, 48
Mean = sum/count= 98
Median= middle term= 97
Mode= number given maximum number of times= 87 (appears 2 times)
x^2 + 3xyz + 2y^2 + 3z^2=98^2+3*98*97*87+2*97^2+3*87^2=2532195

answer Sep 7, 2018 by Hanifa Mammadov

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