1•a-3•b+4•c=100 (1)
4•a-6•b+9•c=999 (2)
2•a-6•b+7•c=879 (3)
(1)x3, get
2•a-6•b+8•c=200 (4)
(4)-(3), get
c=-679
(2)-(3), get
2•a+2•c=120
a=[120-2•(-679)]/2=739
substitute value a & c to (1), get
-3•b=100-1•(739)-4•(-679)=2077
3•a-3•b+6•c
=3•(739)+2077+6•(-679)
=220
3-3+6=220