What is the probability of getting a product of 8 from three throws of a dice?

Answer 1

7/72

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Total possibilities = 6x6x6=216
With first die being 1 there are 6 possible ways of having 8, (1,1,6/1,2,5/1,3,4/1,4,3/1,5,2/1,6,1)
With 2- 5 ways,
With 3- 4 ways,
with 4- 3 ways,
with 5- 2 ways,
With 6- 1 way
Total number of ways = 6+5+4+3+2+1=21
Probability = 21/216 = 7/72